Is there a way to create a query that shows the same results as the defalut linked mentions?

Help
1

I am trying to replace default linked mentions functionality with hope that I can add it to some pages, and not others, and adjust it to my needs.

One of the adjustments I want to make is to display all backlinks pointing to children of a given page. For example, if I have a page called Company, and pages for Google and Meta; with Google and Meta having a property parent:[[Company]]. I would like to see all backlinks to both Google and Meta on the Company page.

Things I have tried

I have tried Search queries. I am a novice with those, and so far I got them working, but have not been able to even get linked mentions to display without unlinked mentions.

I have tried Bases. Bases does a great job of finding backlinks of files that link to a given file. However, with Bases I cannot find a way to display the content of the file. All I get is a list of files.

This can be remedied with the Feed Bases plugin, which is great. However, now the content that is displayed is that of the entire back link note, while the standard backlinks functionality is able to display only the relevant section of the note. Search also has the block: operator that would do the job if I could integrate it with Bases.

Any idea on how to solve this problem? Ideally it would be with the built in query functionality or bases. I prefer to avoid Dataview if I can.

2

Yes, this use case would be ideal for bases, however

no context is possible with bases as far as I know. Though, there have been plenty plugin releases recently, so I might missed one.

Never used search queries in such a case so cant say much there.

Dataview should be able to but I havent done it.

If you want to avoid Dataview, I guess have a look at FRs and see if there is something similar, if not post one. The functionality is there, so probably it will be added to bases at some point.

Maybe someone else has a more helpful answer for you.