---
tags:
- bookmarkTest
---
### Simple List
* (bookmark:: [What are microservices?](https://microservices.io))
And
Multi List
---
tags:
- bookmarkTest
---
### Multi List
* (bookmark:: [What are microservices?](https://microservices.io))
* (bookmark:: [What are microservices?](https://microservices.io))
Also I created BookmarkTest to display all lists
` ``dataview
TABLE WITHOUT ID
bookmark
FROM
#bookmarkTest
WHERE
bookmark
` ``
So my question.
Why is bullet not displayed when there is one item in the list??
TABLE WITHOUT ID
choice(typeof(bookmark) = "array", bookmark, list(bookmark)) AS "Bookmark"
, length(Bookmark) as count
, length(tags) as numtags
, "#" + join(tags, ", #") as tags
FROM
#bookmark
WHERE
bookmark
SORT
file.name ASC
How I can add count of this list items?
yes of course I can do sonething like this
choice(typeof(bookmark) = "array", bookmark, list(bookmark)) AS "Bookmark"
, length(choice(typeof(bookmark) = "array", bookmark, list(bookmark))) as count
Yes, you’re right, it’ll be a repeated conversion…
But, because I still see some lack of knowledge about the metadata structure and syntax in dataview, I think I can’t advance with the suggestion of the code with the command FLATTEN to solve the repetition… (because after FLATTEN it will be necessary GROUP BY and so one).
Maybe you need to solve first your understanding about the tags: tags in content; tags in frontmatter; etc. What’s the difference in using the key field tags or file.tags (or file.etags)?
For example, you write this:
TABLE WITHOUT ID
choice(typeof(bookmark) = "array", bookmark, list(bookmark)) AS "Bookmark"
, length(Bookmark) as count
, length(tags) as numtags
, "#" + join(tags, ", #") as tags
maybe you want to explore this:
TABLE WITHOUT ID
choice(typeof(bookmark) = "array", bookmark, list(bookmark)) AS "Bookmark",
length(bookmark) as count,
length(file.etags) as numtags,
join(file.etags) as tags